LOGARITHM HELP (1 Viewer)

Dylanamali · Mar 2, 2012

Solve for x: 2^{x^}²3^x+1= 108.

Solve for x: (square root of 2)^{x^2} = 8^x/4

[HR][/HR]

deswa1 · Mar 2, 2012

For 1...

Take logs of both sides. Seperate the LHS into sums of logs. Turn it into a quadratic by 'pulling' the powers down. Solve the quadratic.

Good luck

SpiralFlex · Mar 2, 2012

And for 2

$\ln (\sqrt{2}^{x^2})=\ln(\frac{8^x}{4})$

$\frac{1}{2}x^2\ln 2=\ln (2^{3x})-2\ln2$

$\frac{1}{2}x^2\ln 2 =3x\ln 2- 2\ln 2$

$\frac{1}{2}x^2-3x+2=0$

$x^2-6x+4=0$

Remember to always check somefin.

Drongoski · Mar 2, 2012

Dylanamali · Mar 2, 2012

thanks everyone.

Another question:

f(x) = 2x + Inx, find f^-1(2). Give reasons.

LOGARITHM HELP (1 Viewer)

Dylanamali

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deswa1

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SpiralFlex

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Drongoski

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Dylanamali

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