The latus rectum of a parabola has endpoints (-2, 3) and (6, 3). Find two possible equations for the parabola.
All I've done is found the equation of the latus rectum, which is y = 3. I'm not sure what to do next.
Answers are:
x²-4x-8y+12= 0 and x²-4x+8y-36= 0
All I've done is found the equation of the latus rectum, which is y = 3. I'm not sure what to do next.
Answers are:
x²-4x-8y+12= 0 and x²-4x+8y-36= 0