integration... (1 Viewer)

[ashokkumar]

integrate (x^2-1)/(x^2+x-6)

 

[Trebla]

integrate (x^2-1)/(x^2+x-6)

Use the fact that the integrand can be written as 1 - (x + 7)/(x² + x - 6) then split the second term into partial fractions giving 1 + 1/5 [4/(x + 3) - 9/(x - 2)]

 

[ashokkumar]

i got.. x - 8/5ln(x+3) + 3/5ln(x-2) + C... Is that right?