watatank
=)
hey i was wondering if anyone could help me out with integration by parts?
I [y3.e-y/2 dy] limits: 0--> infinity
thanks
I [y3.e-y/2 dy] limits: 0--> infinity
thanks
Last edited:
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integration by parts (1 Viewer)
- Thread starter watatank
- Start date
Slidey
But pieces of what?
- Joined
- Jun 12, 2004
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- HSC
- 2005
Integrate the exponential so that eventually y^3 becomes a constant:
=[-2y^3.e^(-y/2)] + 6*Int y^2.e^(-y/2) dy
Int y^2.e^(-y/2) dy
= [-2y^2.e^(-y/2)] + 4*Int y.e^(-y/2) dy
Int y.e^(-y/2) dy
= [-2y.e^(-y/2)] + 2*Int e^(-y/2) dy
= [-2y.e^(-y/2)] + [-4e^(-y/2)]
Now just add them all together.
BTW, I don't think 4unit integrals have limits to infinity.
=[-2y^3.e^(-y/2)] + 6*Int y^2.e^(-y/2) dy
Int y^2.e^(-y/2) dy
= [-2y^2.e^(-y/2)] + 4*Int y.e^(-y/2) dy
Int y.e^(-y/2) dy
= [-2y.e^(-y/2)] + 2*Int e^(-y/2) dy
= [-2y.e^(-y/2)] + [-4e^(-y/2)]
Now just add them all together.
BTW, I don't think 4unit integrals have limits to infinity.
watatank
=)
sweet...thanks heaps man
