Inequality graphing problem... Need help (1 Viewer)

[Zorren]

Hey guys,

I'm kinda stuck on this question and I'm looking for some help, any response would be awesome.

(5x^2+1)/(2-x) > 0

 

[Carrotsticks]

Hey guys,

I'm kinda stuck on this question and I'm looking for some help, any response would be awesome.

(5x^2+1)/(2-x) > 0

We can move the (5x^2+1) over to the other side without flipping the inequality.

The reason why is because for ANY value of X (that you know so far), it's impossible for 5x^2+1 to be negative or equal to zero.

In other words, 5x^2+1 is guaranteed to be positive and not equal to zero, so we can divide both sides by 5x^2+1 safely.

So the question is equivalent now to solving 1/(2-x)>0.

Also, I have moved this question to the Extension 1 section, as unknown denominators are in the Extension 1 course.

 

[Zorren]

Thanks Carrotsticks! I really appreciate your help

 

[Carrotsticks]

Why not go a step further and say (by the same logic) it is equivalent to solving 2-x>0 ?

Was hoping that OP could try to figure it out from here, as they've now been exposed to that kind of logic.

 

[turntaker]

Zorren hi