C clicker Member Joined Feb 23, 2004 Messages 30 Mar 13, 2005 #1 when lead oxide is heated with carbon, metallic lead is formed. 2PbO (s) + C (s) ------> 2Pb (s) + CO2 (g) if 87.3g of lead oxide were mixeed with 2.62g of charcoal (carbon), what mass of metallic lead would be formed ?
when lead oxide is heated with carbon, metallic lead is formed. 2PbO (s) + C (s) ------> 2Pb (s) + CO2 (g) if 87.3g of lead oxide were mixeed with 2.62g of charcoal (carbon), what mass of metallic lead would be formed ?
miss_b still obsessed... Joined Jan 14, 2005 Messages 770 Location Melbourne Gender Female HSC 2005 Mar 13, 2005 #2 m(PbO)=87.3g M(PbO)=223.19g/mol n(PbO)= m/M = 0.3911466mol m(C)=2.62g M(C)=12g/mol n(C)= m/M = 0.218333mol n(PbO) : n(C) =2:1 So C is in excess n(PbO):n(Pb) =2:2 n(Pb)=0.3911466mol M(Pb)=207.19g/mol m(Pb)=M*n= 81.0g Last edited: Mar 13, 2005
m(PbO)=87.3g M(PbO)=223.19g/mol n(PbO)= m/M = 0.3911466mol m(C)=2.62g M(C)=12g/mol n(C)= m/M = 0.218333mol n(PbO) : n(C) =2:1 So C is in excess n(PbO):n(Pb) =2:2 n(Pb)=0.3911466mol M(Pb)=207.19g/mol m(Pb)=M*n= 81.0g
miss_b still obsessed... Joined Jan 14, 2005 Messages 770 Location Melbourne Gender Female HSC 2005 Mar 13, 2005 #4 Sorry, made a mistake... Corrected it now with working out