How do I do this question?????? (1 Viewer)

[constexpr]

 

[carrotsss]

It starts at two, then heads to 6 by pi/2, then heads back to 2 by pi, then heads back to 6 by 3pi/2 and then head back to 2 by 2pi

therefore 4*4=16m

 

[Luukas.2]

Find the position of the particle at seconds and at seconds.

Then, find the equation for the velocity of the particle and see if there are any times on where . If there are, find the position at those times as well.

Then, find the distances of each separate period of motion within and sum them.

 

[Luukas.2]

A faster way is to recognise that is an equation of simple harmonic motion.

Since , it follows that the amplitude of motion is A = 2 m.

The period of the motion is , and over each complete period, the particle travels a distance of 4A in returning to its starting position. Here there are two complete periods.

Total distance travelled is 2 x 4A = 8A = 8 x 2 = 16 m.