i did this question before but literally forgot how lmfao i need help on b!!
astraaaaaah New Member Joined Sep 6, 2021 Messages 17 Gender Female HSC 2022 Nov 23, 2021 #1 i did this question before but literally forgot how lmfao i need help on b!!
jazz519 Moderator Moderator Joined Feb 25, 2015 Messages 1,955 Location Sydney Gender Male HSC 2016 Uni Grad 2021 Nov 23, 2021 #2 K = [CH3OH] / [CO] [H2]^2 let [CH3OH] = x they say [CO] = [CH3OH] [CO] = x 2.25 = (x) / (x) [H2]^2 2.25 = 1/[H2]^2 1/2.25 = [H2]^2 take the square root and you have the asnwer
K = [CH3OH] / [CO] [H2]^2 let [CH3OH] = x they say [CO] = [CH3OH] [CO] = x 2.25 = (x) / (x) [H2]^2 2.25 = 1/[H2]^2 1/2.25 = [H2]^2 take the square root and you have the asnwer
astraaaaaah New Member Joined Sep 6, 2021 Messages 17 Gender Female HSC 2022 Nov 23, 2021 #3 jazz519 said: K = [CH3OH] / [CO] [H2]^2 let [CH3OH] = x they say [CO] = [CH3OH] [CO] = x 2.25 = (x) / (x) [H2]^2 2.25 = 1/[H2]^2 1/2.25 = [H2]^2 take the square root and you have the asnwer Click to expand... Thanks! I see where I went wrong now, really helpful
jazz519 said: K = [CH3OH] / [CO] [H2]^2 let [CH3OH] = x they say [CO] = [CH3OH] [CO] = x 2.25 = (x) / (x) [H2]^2 2.25 = 1/[H2]^2 1/2.25 = [H2]^2 take the square root and you have the asnwer Click to expand... Thanks! I see where I went wrong now, really helpful