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Help please (1 Viewer)

rawker

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Aug 27, 2004
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Newcastle
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HSC
2006
the cost of running a car at an average speed of v km/h is given by c= 150 + (v^2 / 80) cents/km. find the average speed, to the nearest km/h, at which the cost of a 500 km trip is a minimum


i derived that, so that i had dc/dv = v/160 , which then i made = 0
v=0....
d^2c/dv^2 = 1/160 > 0 (min)



then what?
 

yodajones2000

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May 21, 2006
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2007
I am too lazy to figure it out now. But this is one of those questions with more than one possible answer.
 

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