electrolysis (1 Viewer)

[crammy90]

K+ + e- --> K -2.93V
H2O + 2e- --> H2 + 2OH- -0.83V (water reducing - this 1 goes)
Anode (+)
2I--> I2 + 2e- -0.62V (this 1 goes)
2H2O-->O2 + 4H+ + 4e- -1.23V

do we add the charges when writing overall equation or do -0.83- the 1.23 to get a lower number or is it -0.83-(-0.62) which makes it a plus?

 

[minijumbuk]

I don't really understand your question, sorry.

 

[danz90]

i don't really understand either LOL

but all I can say is, electrolysis is a non-spontaneous reaction, converting electrical energy into chemical energy. so obviously ur overall E value will be less than 0 (ie negative), since energy is not being produced, but being used up.

electrolysis, i believe, isn't part of the core section. im not sure about other options, but only industrial focuses on it in Electrolysis of NaCl.

 

[SkimDawg]

I think this should've been posted in the shipwrecks section, it looks like a question only for that option