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Definite Integral by parts question (1 Viewer)

Thread starter MC Squidge
Start date May 16, 2009

MC Squidge

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#1

Integral of [(2x^3)e^(x^2)] with respect to x between 0 and 1

Trebla

Administrator

Administrator

#2

$u=x^2\Rightarrow du=2x\,dx\\dv=2xe^{x^2}\,dx\Rightarrow v=e^{x^2}\\\\\int _0^1 2x^3e^{x^2}\,dx=\left [x^2e^{x^2}\right]_0^1-\int _0^1 2xe^{x^2}\,dx\\\\=e-\left[e^{x^2}\right]_0^1\\\\= 1$

MC Squidge

BOS' Apex Predator

#3

fanx bro

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