Cssa (1 Viewer)

[yibbon]

A Note from the Moderators:
Please keep in mind not to give out the actual questions or a copy of the paper as there are copyright issues, not the mention the fact that some students may do the same paper as you at a different date and it is still within the security period.
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How did everyone fare? I dropped PLENTY of marks...found it pretty hard.

 

[-Onlooker-]

Easier than previous years IMO. Wonder if anyone in this forum would get >90%

 

[5647382910]

A hell of a lot more easier than previous trials
graphing was pretty awkward and so was that trig volumes question... so much avenue for mistakes
GRRRRRR! couldnt get that final inequalities question and the locus circle geo and that conics q where you had to find PQ... GRRR!
Altogether a relatiovely easy paper, maybe its because mechanics was taken out with no replacement q's. expecting 80-90/105

and btw.. did everyone get ln2 for the area under the curve in q1?

 

[lyounamu]

lol it was okay. I should get around 100+/120

 

[yibbon]

A hell of a lot more easier than previous trials
graphing was pretty awkward and so was that trig volumes question... so much avenue for mistakes
GRRRRRR! couldnt get that final inequalities question and the locus circle geo and that conics q where you had to find PQ... GRRR!
Altogether a relatiovely easy paper, maybe its because mechanics was taken out with no replacement q's. expecting 80-90/105

and btw.. did everyone get ln2 for the area under the curve in q1?

I got In[2] as well

 

[Dumbledore]

lol it was okay. I should get around 100+/120

man that would be an awesome mark, did u cater in for careless mistakes? or just how many u think you got wrong?

how much would 100/120 raw scale to for HSC mark?

 

[lyounamu]

man that would be an awesome mark, did u cater in for careless mistakes? or just how many u think you got wrong?

how much would 100/120 raw scale to for HSC mark?

10 marks for sure. Silly mistakes probably less than 10. So 100+

100/120 = 96 I reckon?

 

[kwabon]

i think harder 3 unit will be the death of me ....
everything else was okay ....

 

[-Onlooker-]

man that would be an awesome mark, did u cater in for careless mistakes? or just how many u think you got wrong?

how much would 100/120 raw scale to for HSC mark?

That really depends on the general difficulty of the exam.

If the HSC paper as difficult as this CSSA paper; I'll say 100/120 would be 93-95 %

 

[5647382910]

with the circle geo q for part ii)
i said that 2 sides of the triangle are constant therefore the third side (the side the q was asking for) is always constant
is that right?

 

[kwabon]

10 marks for sure. Silly mistakes probably less than 10. So 100+

100/120 = 96 I reckon?

more than that ... i reckon it also depends on the paper and how hard it was ... so if this was the HSC, i reckon that would get you 98/97 easy.

EDIT: -Onlooker- beat me to it

 

[-Onlooker-]

with the circle geo q for part ii)
i said that 2 sides of the triangle are constant therefore the third side (the side the q was asking for) is always constant
is that right?

Without reference to the Q; I can see a flaw in your argument.
What if the subtended angle between the two sides varied? the length of the third side would then vary too

 

[5647382910]

Without reference to the Q; I can see a flaw in your argument.
What if the subtended angle between the two sides varied? the length of the third side would then vary too

Shit!
what was the correct argument then?

 

[yibbon]

How about the z^5 = 4+4i question, did anyone find more then one root? I sure didn't.

 

[-Onlooker-]

Anyone else fudge a few questions in hope of their teacher becoming oblivious to their conniving ways?

 

[5647382910]

How about the z^5 = 4+4i question, did anyone find more then one root? I sure didn't.

aha ye
i think the answer was ((32)^1/10)cis((pi/20) + 2pik/5) --> k = 0,1,-1,2,-2

 

[-Onlooker-]

How about the z^5 = 4+4i question, did anyone find more then one root? I sure didn't.

LHS = r^5 cis 5(theatre ) RHS = 4root2 cis (pie/4 )

r = root 2
theatre = pie/20 + 2 n pie/5

then throw in a few n values to get the 5 solutions in mod-arg form



In reply to 5647382910; I didn't attempt; time constraints.

 

[Dumbledore]

Anyone else fudge a few questions in hope of their teacher becoming oblivious to their conniving ways?

i fudged the end of induction and the sequence one

 

[ratcher0071]

Did the Independent .


:mad1:

 

[Dumbledore]

imo everything in this paper was either, really easy or really hard, not much in between