M Mumma Member Joined May 19, 2004 Messages 586 Location Sydney Gender Male HSC 2006 Mar 29, 2006 #1 Attatched is the entire question, parts (a) to (c). (a) and (b) I can do pretty easily, but (c) im not sure on how to proceed with.
Attatched is the entire question, parts (a) to (c). (a) and (b) I can do pretty easily, but (c) im not sure on how to proceed with.
L littleboy New Member Joined Dec 10, 2004 Messages 26 Gender Male HSC 2006 Mar 30, 2006 #2 using part b and divide both sides by z^3. so it becomes : z^3 + 1/Z^3 +1 = (z+1/z -2cos2pi/9)(z+1/z-2cos4pi/9)(z+1/z - cos8pi/9) take out 8 from the right hand side and equate the real parts
using part b and divide both sides by z^3. so it becomes : z^3 + 1/Z^3 +1 = (z+1/z -2cos2pi/9)(z+1/z-2cos4pi/9)(z+1/z - cos8pi/9) take out 8 from the right hand side and equate the real parts
