N nrumble42 Member Joined Oct 3, 2016 Messages 64 Gender Female HSC 2017 Dec 26, 2016 #1 Find the real numbers x and y such that: (1+i)x + (2-3i)y = 10 Sent from my SM-G920I using Tapatalk
I InteGrand Well-Known Member Joined Dec 11, 2014 Messages 6,109 Gender Male HSC N/A Dec 26, 2016 #2 nrumble42 said: Find the real numbers x and y such that: (1+i)x + (2-3i)y = 10 Sent from my SM-G920I using Tapatalk Click to expand... Equate real parts: x + 2y = 10. (1) Equate imaginary parts: x – 3y = 0. (2) Solving simultaneously yields x = 6 and y = 2.
nrumble42 said: Find the real numbers x and y such that: (1+i)x + (2-3i)y = 10 Sent from my SM-G920I using Tapatalk Click to expand... Equate real parts: x + 2y = 10. (1) Equate imaginary parts: x – 3y = 0. (2) Solving simultaneously yields x = 6 and y = 2.
M Mahan1 Member Joined Oct 16, 2016 Messages 87 Gender Male HSC 2014 Feb 13, 2017 #3 nrumble42 said: Find the real numbers x and y such that: (1+i)x + (2-3i)y = 10 Sent from my SM-G920I using Tapatalk Click to expand... Another slightly different method is to multiply the original equation by (1-i) then equation only the imaginary parts yields: and equating the real part of the original part shows
nrumble42 said: Find the real numbers x and y such that: (1+i)x + (2-3i)y = 10 Sent from my SM-G920I using Tapatalk Click to expand... Another slightly different method is to multiply the original equation by (1-i) then equation only the imaginary parts yields: and equating the real part of the original part shows