Challenge questions (1 Viewer)

[tam89]

mmm... need help with these questions. I don't know how to begin the question.. i have no idea how to answer them! Please provide some feedback. Thanks

See attachment below.

 

[Stan..]

The third is pretty simple, It is an property of definite integrals.
y=f(x) and y=f(a-x) are reflections of eachother in the vertical line y=a/2
Thus, Just evalutate the intergals.
F(a)^2 = F(a)^2
Thus DIn(a,0) F(x)dx = DIn(a,0) F(a-x)dx

 

[haboozin]

way easier way

use sub u = pi - x

(u needa do it twice)
or a = pi - x

oops i forgot
its one of those

and u just do it twice and it comes out so nicely
its in last yrs sydney boys high trial, if u wanna find out for sure.

 

[Stan..]

From what I can gather about what your saying, it implies a phase shift of a trig function. Maybe Sin(Pi/2 - x) = Cosx?