acceleration/velocity question (1 Viewer)

[woho]

Hiya all

Having problems with this 3unit question, please help?

"The acceleration of a particle is given by a = x(x^2 – 3)^4 cm/s^2. If the particle is initially 2 cm to the right of the origin, moving with a velocity of 4cm/s, find the velocity of the particle in terms of x"

The only thing i can think of is integrating ∫a to get d/dx(1/2 v^2), but it looks impossible to integrate...

Thanx

 

[Azamakumar]

Let x^2 - 3 = u.

Then du = 2x

Expand to get 1/2v^2.

 

[martinb]

Hey,

Solution attached - hope it helps

 

[woho]

Ok that makes sense

Thanks heaps!!