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  1. D

    Another one

    Thanks acmilan.
  2. D

    Another one

    i am sorry guys i think i must have copied down the question wrongly. i went back and found out the question actually read prove: (tanx + 1/sec x) - (cotx+ 1/cosecx)
  3. D

    Another one

    i have tried both ways and i am still lost. just to clarify its (tanx+1)/sec x.
  4. D

    Another one

    How do you prove that (tanx + 1/sec x) - (cosec x/sec^2x) is a constant?
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    Yet another problem

    Thanks nobuo!
  6. D

    Yet another problem

    This one involves proving trig identities prove (tanx + cotx - 1)(sinx + cosx) = (secx/cosec^2x) + (cosecx/sec^2x)
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    Another problem

    Thanks acmilan and dreamerish, i am getting smarter by the minute.
  8. D

    pretty bad at AP and GP

    wow!that looks complicated. thanks a lot rama.
  9. D

    Another problem

    I am trying to solve a trig identity equation without much luck solve sin^2x - 3sinxcosx+2cos^2x=0 i have been going around in circles with this one and my head is starting to hurt.
  10. D

    pretty bad at AP and GP

    i think its geometric, but it doesnt say
  11. D

    pretty bad at AP and GP

    i still cant figure it out
  12. D

    pretty bad at AP and GP

    The sum to 'n' terms of a certain series is 2^n+1 - 2. Prove that the nth term is given by 2^n+1 - 2^n. I tried solving this by writing 2^n+1 - 2 in the form of ar^n - a/r-1 and i got stuck is there a better way?
  13. D

    Another question

    Thanks so much acmilan
  14. D

    Another question

    If x, y, x+y are in arithmetic sequence, and x, y, 20 are in geometric sequence show that y=0 or y=10.
  15. D

    Help!

    Thanks you all very much for that answer. i didnt think it was that easy.
  16. D

    Help!

    How do you prove that the logarithms of a set of numbers in G.P are in A.P? i appreciate any help i can get on this.
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