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Mind posting the questions and so we could do it for u?

Do you happen to be studying in the Australian International School of HK??

Does anyone have biology CSSA Past papers and worked solutions?? Please post them up if you have them ... Thx in advance!

COol ... THX that's greatly appreciated.. it's hard to check my work right now for those qs im uncertain abt.. thx ;)

Hi, sorry was away.. Well as i have only done 3-4, so far :P i reckon the Area of triangle PAC is 16, but since someone else said it's 6.... maybe im just wrong, and in question 4b) iii) i think it shud be -12x^2 - 12x -3 = 0. just missed an x out... Another thing im not sure if it's...

Acmillan, not to insult u or anything, but i think maybe coz you were doing ans for Qs 3-6, there's quite some careless mistakes in there...

acmillian.... just wonderin.. for question 3 c) v) .... is ur solution wrong?? i think it's 16 isn't it... if not can u explain ur answer? thx

Well, it's safer to just do it... in case ! :D

Hi, thx for the effort... but i don't get what formula you used for part 4.. You didn't use n = CV .... how come urs is like n = V / something :O ?? Looking forward to ur reply... exams later today :P Thx in advance! -- is there like anything on this in the chemistry context...

Yea... exactly, that's why i dunno how to do it :P But in da exam are we allowed to bring in a mole calculator or wuteva u said??

can't we just use V = n/C ?

no.. are u saying that n = 24.97? i thought u said n= m/M .'. n(S) = 10^7 / 32.06 = 311915.16 is right tho :S

- "where did u get ur 24.79?" anyway keep on going..... what i would do is: n=CV but... we are trying to find V... and C is unknown... so.. am i supposed to do something else first?

I dun realli get what u did but is this right?? Mass of S: 0.1% x 10^7 = 10 000kg = 10^7 grams M(S) = 32.06 n= m/M .'. n(S) = 10^7 / 32.06 = 311915.16 ... hmm i got a feeling im wrong..

lol yea... it's just me... hehe, well spotted. Anyways, would anyone mind posted on the correct answers as well?

Cool... thx ;)

Has anyone done the 2004 CSSA HSC Trial papers?? I was just wondering for question 23... "Coal, containing 0.1% sulfur, is burned in a power station. Calculate the volume of sulfur dioxide released at 25 degrees Celsius and 100kPa when 10.0 million kg of coal is burned." Supposedly, to...

(x+2)^8 T_(r+1) = 8 C_r x^(8-r). 2^r T_r = 8 C_(r-1) x^(9-r) . 2^(r-1) Let C_r, and C_(r-1) be the coefficients of the terms.... then [C_(r+1)]/ C_r = [8 C-r 2^r] / 8 C_(r-1) 2^(r-1) = (18-2r)/r C_(r+1) >= C_r if 18 - 2r >= r 18 >= 3r...

:S im lost with that.... do u think u cud explain it more?

Why wouldn't people want to be qualified for it!!?? What is this long term disadvantage are u referring to anyways?? And also if anyone can pls tell me... what are the disadvantages in applying for EAS?