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I'm doing this subject next session and somebody told me that the lecturer gives everyone a generic access code for mathxl. Could somebody who has done this subject before tell me if this is the case? Thanks

Yeah COMM101 is really easy. Most people don't even read the textbook. Anything that is important they go over in tutorials anyway. Btw, would anyone be willing to sell the marketing textbook to me? :p

anytime :)

To find velocity: a=dv/dt=-0.4v^3 integral of dv/-0.4v^3 1/-0.4(1/-2)1/v^2 with integral limit things being 0 and 60= t-0 1/0.8(1/v^2-1/60^2)= t v= ((1/60^2+0.8t)^-1/2)m/s when t=4s, v=0.559m/s downwards To find position: v=sd/dt= ((1/60^2+0.8t)^-1/2) integral of (1/60^2+0.8t)^-1/2dt...

haha. maybe ;)

lol. i go 2 uow :haha:

yea. lol. u?

just go 2 syd. lol. or uow :)

lol!