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I was wondering if anyone had some insight they could give me into a comparison of science courses for USyD, UNSW and ANU - specifically Bachelor of Advanced Science/Advanced Studies (at USYD as a Dayell Scholar), Bachelor of Advanced Science/Computer science (at UNSW) and the Bachelor of...

Very sorry if this is a pretty stupid question, probably just a pre-exam freakout: In a beaker, 50 mL of 1.0 mol L−1 CH3COOH is reacted with 30 mL of 0.70 mol L−1 NaOH. (Ka of CH3COOH = 1.7 x 10−5) Calculate the pH of the final solution My confusion is how are you supposed to calculate the pH...

Firstly, epic exam to everyone involved in making it - tough multi-choice section, the free-response part required problem-solving, very good paper. I'll hold my questions for now until the solutions are posted (When would that be?), but just quickly - The last question talked about Tollen's...

Oh so is this going to be like mastermind where we keep guessing? Nah, I'm kidding, but that's pretty interesting that only 1 of the 4 identified was correct. Are the 3 that most answered amongst 1, 2, 3, 4? The only other question I could think of being the "hardest" question was 6

I agree that 8 seems like the one less than 50% got right, but think the >70% ones are 1,4 and 7 (Though I am not too certain about 7, perhaps it was 2? I would say 3, but not a lot of people are too comfortable with that notation IMO). I did think this was a lovely multi-choice section...

Actually on the second question, is the method: (Apologies for not using right formatting): - Integration by parts on the middle one, which gets the inequality (As it is greater than 0 by inspection) I_(n-1) < e/n - Using this to show er < n+1 - There will always be an n to fulfill this

2 Questions: 1) is Q22 a) correct, because I'm under the impression it should be 100j (Instead of j) in the given equation 2) How exactly do you go about showing Q23? I imagine it is insufficient to show the integral approaches 0 as n approaches infinity, therefore there will always exist an n...

A lot, thank you very much

What I mean is if the oxidising agent that you add is acidified, then irrespective of whether the aldehyde is oxidised to the ketone, the sodium carbonate will still produce CO2 gas. The same applies for a litmus test

Also, forgot to put it in OG question, what is the identifying test for alcohols? (Just whether it has formed, not differentiating them)

1. Is there a chemical test to identify an ester (Non-spectra based)? This was one of the questions on an HSC paper, and they don't indicate any other than smelling it, so I assume not 2. The oxidation of an aldehyde to form a carboxylic acid has to be done with an acidified oxidising agent, so...

Apologies for questions, probably been answered before, just having a bit of a pre-HSC panic. 1. How come the intermolecular bonds formed with a carbonyl group on a molecule (i.e. carboxylic acid, or the non-carbonyl oxygen in the ester group) is defined as forming a dipole-dipole bond, but the...

Did anyone have any schools that they thought the trials papers for were difficult? I'm looking for Phys, Chem, 4U and 3U math (The schools I've looked at are Ruse, Baulko, NSB and Sydney Grammar) Thanks

I'm not sure how right the answers are, seeing as it says 2 for 10 (MCQ) when it's 3, so dw. I haven't checked the other ones though

Personification?

Does anyone have any suggestions for resources available to use Fahrenheit 451 as a related text for 1984? Also, for people who did study 1984, were there any other books that were particularly useful as a related text? (Given we are studying love in 1984 rather than control/power) Thanks

Thanks guys - turns out I just pulled a bit of a dumb :) Out of curiosity, does anyone have any ideas to prove the sum of cosine expression I thought I needed?

Not sure how to solve the following: (1+cos(a)+isin(a))^k+(1+cos(a)-isin(a))^k = (2^k*2)*cos(ka/2)cos^k(a/2) I can get it down to proving: 1 + cos(a) + cos(2a) + .... cos(ka) = 2^k*cos(ka/2)cos^k(a/2) But don't know where to go from there. I'm almost certain you need to use: 2cos(A)cos(B) =...

I'm not sure but is this even true? Just subbing in a=1, b=2, c=3, d=4: x = 2.5 = 1.5 * 0.5 * -0.5 * -1.5 Which isn't 4? Unless I'm understanding the question wrong here

Here's a brief rundown, reply if you want a more detailed response. Take 3 points A, B and C. Draw lines AB and BC, labelling their midpoints z and y respectively. Then, draw perpendicular lines at Z and Y such that they intersect with each other at a point (say O). You can easily prove...