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For part (iii): $\noindent \int_{4}^{6} f'(x)dx = f(6) - f(4) = -6, (A_3 = 2*3) \\ \\Since \int_{2}^{4} f'(x)dx = -\int_{0}^{2} f'(x)dx \\ \\ \int_{0}^{2} f'(x)dx = f(2) - f(0) = 4 \\ \\ Given f(0) = 0 \\ \\ \therefore f(2) = 4 \\ \\ \int_{2}^{4} f'(x)dx = f(4) - f(2) = -4 \\ \\ \therefore f(4)...

Thank you InteGrand! <3 Much appreciated.

Hey can anyone help me with these 2?

Thank you very much InteGrand! :)

Hey, thanks for your reply! I don't fully get it. Sorry but could you explain further with full working out please?

Hey there can anyone help me with this question? [emoji4] Cheers, AlarmBell.

$\noindent Complex roots come in conjugate pairs only when the coefficients of the polynomial are real. \\ \\Since the coefficients of (2-i)z^2-(1+i)z+1=0$ $ is complex, the other root is not a conjugate of the one you found.$