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Ok. Thanks. was confused because of my tutor's reason (mentioned in the OP). Also after reading this added to the confusion: https://www.logicallyfallacious.com/tools/lp/Bo/LogicalFallacies/173/Sunk_Cost_Fallacy

Hi, Question: James has a ticket for a football match in Sydney for which he paid $45. On the day of the game he takes the train to Sydney Olympic Park, which costs him $3. When he arrives, he realizes that the game is taking place in Moore Park instead. He can take a taxi for $50 and arrive...

How come? I was thinking it wouldn't be linear but eventually it has to reach zero which A doesn't indicate Also, is there an equation that relates "solubility" with "time"? Like in Physics, a = Gm/r^2 we can say it would look like (A) because as r varies, a varies inversely

https://9eeba4054ee764a743f35bb25b5f907e66151207.googledrive.com/host/0ByEFYhkkDQBKUmxzb0Q4MEswQ3c/Year%2012%20-%20HSC/Chemistry/Past%20Trials/Girraween/Girraween%202011%20Chemistry%20Trials%20&%20Solutions.pdf how would I do q3 and q8? and also, is the answer to q13 D?

http://imgur.com/LJpmGsZ For (ii) I keep getting an extra "+sin(phi)" at the numeratorbecause of the product rule? for (iii) I can't show it but does that imply that dtheta/dt also equal zero? sounds odd. because, if NT is tangential, angle NTO = 90, angle NOT = 180-theta which means phi =...

so I should always look for the angle between the diameter and segment?

I get that, but why did he/solutions find angle PBA? I thought angular velocity is respect to positive x-axis (direction of angles) so I should find angle PBC?

https://9eeba4054ee764a743f35bb25b5f907e66151207.googledrive.com/host/0ByEFYhkkDQBKUmxzb0Q4MEswQ3c/Year%2012%20-%20HSC/Maths/Past%20Trials/James%20Ruse/4U/James%20Ruse%202014%204U%20Trials%20&%20Solutions.pdf q16 a i) why is the angular velocity about B = -pi/2 ? It makes sense, because it...

why is there a horizontal force of N? Is it because the ring touches and pulls against the rod so the rod has to have an opposing force?

A particle P is undergoing uniform circular motion, while being pulled by two strings, one connected at A with the other string connected at B, vertically under A. At A, there is a hollow ring that is suspended. I drew the tensions in string AP, one tension going away from B towards P and...

No, but she just does questions from the textbook, doesn't show us many concepts and ways to do it

Thank you. Is there some place that shows us all the possible techniques used in this topic? Ive only heard about this right now and are there any specific exercises that have these types of problems?

*HSC 2012 How would I do this? (ii) Consider three identical separators to divide the 10 coins into 4 boxes, total = 13 items, including 3 identical separators and 10 identical coins. This was from Terry Lee's solutions, he referred to his book but I don't have it. What's a "divider" and can...

Makes a lot of sense, thanks. Also, about the swapping of powers, what if they ask for the 5th term (T5)? This would depend on where I put the powers [ 'n-r' and 'r' ] wouldnt it? Which case is correct?

So was I wrong? Im confused. If i expanded like the way I did in the exam and got a fraction, should I reverse the powers too?

But if n = 4r, and n = 12 (which was in part (i)), then r = 3. the term is 12C3 (2x^3)^9 (-1/x)^3 which isn't constant

(x+y)^n = ^nC_0 x^{n}y^{0} + ^n C_1 x^{n-1}y^{1} + ... + ^n C_{r} x^{n-r}y^{r} + ... + ^n C_{n}x^{0}y^{n} Is this always the way you expand it? Because I was doing a question where their general term was: ^n C_{r} x^{r}y^{n-r} The powers are swapped around. Although it is symmetrical, this...

Re: HSC 2015 4U Marathon \delta V = \frac{1}{2}(2x)(2x)sin(60)\delta y \delta V = \frac{1}{2}(4x^{2})(\frac{\sqrt{3}}{2}) \delta y \delta V = \sqrt{3}(1-y^{2}) \delta y V = \int_{-1}^{1} \sqrt{3}(1-y^{2}) dy V = 2\sqrt{3} \int_{0}^{1} 1 - y^{2} dy

What if it's method of slicing bounded by y = (x-1)^2 -1 by x = 1 rotated only 180 degrees?

So when rotating around y = x, you would find the normal volume with method of slicing and then after that you halve the final answer?