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Anyone would like to try to work out and explain these root of unity questions? (: 1. Let w, a complex number, be the cube root of unity. (a) find possible values of w. (b) Show w^2 + w + 1 = 0 (c) Hence simplify, (1+w)^6 2. Given w, a complex number, is a root of equation z^3-1=0...

Ah bro, that's still wrong LOL. I got the answer for every problem on top. If you guys want me to post it?

nice

Solutions to 2A

Yeppe @Triage, I definitely think to get the solutions for 2B, you need the Argand Diagram on 2A. Also quesiton 6 is difficult, don't know the answers tbh.

I don't understand what you did?

If anyone would like to try to solve these questions, then you're welcome! 2) If |z| = 1, where a is a positive number, show that: a) arg(z+1) = 1/2argz Easy(done) b) |z+1| = 2sin(arg(z-1)) 6) On the Argand diagram, the points P, Q, and R represent the complex number p, q, & r...

Thank you!!

I need help with this question, if anyone wants to solve. It's a Complex Number question. 1. A(z) and B(w) form an equilateral triangle with the origin. With argw>argz a) Express w in terms of z. Which is w=zcis60, which is pretty easy. b) Prove that z^2 + w^2 = zw <- Can anyone work this...

I am looking to travel to the tutor's house/place. Around Liverpool/Fairfield/Cabramatta/Canley Vale

Hey guys, I urgently need a Chemistry tutor as I cannot self study for it. I lose my attention span, and I don't really know what to study for. Plus, I don't have enough resources so could any of you B.O.S users, recommend a Chemistry tutor? Don't suggest Peak Science or James An. I don't want...

Good answer @Ipodtouch! Anyone else wanna try the other questions?

Answers are posted!

AHAHA! It's correct? The answers are: z= 2+i, 2-3i. Dammit, I can't get too it

@Ipodtouch For that question. Isn't it |a+ib|^2 + 2i(a-ib) = 4i + 7 (a+ib)^2 + 2ia +2b = 4i + 7 a^2 + 2iab - b^2 + 2ia + 2b = 4i + 7 2iab + 2ia + a^2 - b^2 + 2b = 4i + 7 Equate the real part and the imaginary part right? (Re): a^2 - b^2 + 2b = 7 (Im): 2iab + 2ia = 4i b + 1 = 2...

Nice! It's absolutely correct! :)

How did you get to z = 2 + i , 2 - 3i?

Since this is a kind of Complex Number marathon thread. Here's a few questions, for you geniuses!

Since this is a kind of Complex Number marathon thread. Here's a few questions, for you geniuses!