I don't know what you're on about but I think the form of my argument is wrong. Contradication shouldn't be a conclusion
I didn't ask you because I thought I interpreted it correctly but thanks for reaching out to me :)
Here is the exchange -
PSYC1011 - talking about guy clothes and recommendations
Z - "arent u a girl" (paraphrased)
PSYC1011 - "no, how did u arrive at that conclusion?"
Z - "vibe"
PSYC1011 - "pls elaborate, what kind of vibe?"
Z - "it's the vibe... of the thing
i thought you were a white...
Two days ago, I was told the following is not valid:
Argument 1 {
Premise 1: psyc1011's vibe is ________
Conclusion 1: psyc1011 is a female
}
Argument 2 {
Premise 2A: vibe has no judgement
Premise 2B: Argument 1
Conclusion 2: contradiction
}
This is me dissecting what another user said or...
Don't worry about hours studied, worry about tasks completed!
During HSC, I studied by counting hours but it left an inaccurate display of how much work I did, around 30min before my break, I lose focus. Also I was only worried about hour count instead of actually studying, lol.
Halfway...
re: HSC Chemistry Marathon Archive
From google, it's a neutralisation reaction. Take x hydrogen from one, hydroxide from one, unify them to make water. The remaining product is a salt
where x is the number of protonisations the acid does
What are the most applicable and helpful discipline ot study at University? EXCLUDE MEDICINE!
I'd saw Law and Engineering.
Law for immense critical thinking abilities to see clarity in most things and win most arguments, if not all
Engineering for the creative and building abilities...
Why did you do 1 - (18/37)^6? Answer this before proceeding.
The question wants P(>= 1 black before 6th game) = 1 - P(0 blacks) = 1 - (P(red) + P(green)) = 1 - (18/37 + 1/37)^5
You probably missed the green ball OR you did (1 - P(all blacks)) - this is wrong, why?
Thats not the only time to use factor theorem. Factor theorem can be a quick way to check that a guessed factor is a factor. Guesses are usually -2, -1, 1, 2 (kinda leads to david's post but 2u dont need it.)
I required knowledge of x - 2 being a factor of the polynomial by factor theorem demonstarted by Integrand, then it sparked this idea:
x3 - x2 - 4 = x3 - 2x2 + x2 - 4
Then factorising each pair
x2(x - 2) + (x - 2)(x + 2) = 0
(x - 2)(x2 + x + 2) = 0
This is a bit hard to see..
The reason...