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No problem :)

In that case: {\raggedleft5^{x+2}=47^{3x}\\\\ \ln (5^{x+2})=\ln (47^{3x}) \\\\ (x+2)\ln (5)=3x\ln (47)\\\\x(\ln (5)-3\ln(47))=-2\ln (5)\\\\x = \frac{-2\ln(5)}{\ln(5)-3\ln(47)}}

Is that 5^{x}+2 = 47^{3x} or 5^{x+2} = 47^{3x}?

Unless that function happens to be linear, then just divide by the coefficient of whatever you're integrating with respect to.

Same thing happened to me when they uploaded the other safety and wellbeing tutorial. Probably happened to everyone. I'm sure they'll sort it out.

Re: Want to know if you made it into your preferred UNSW course before official offer Gehh, same thing happened to me, guess we have to wait until tomorrow when we can call/get our letters... ANY IDEAS ANYONE?!

Hi! I'm Fred and I completed my HSC in 2012 scoring 95 in Maths Ext. 1 and 90 in Maths Ext. 2 externally. This year while studying Maths units at UNSW, I'll be offering tutoring in the City and Inner West area, either at your place or mine in Newtown. I'll be offering tutoring for: Years 7-10...