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I can give you around 85~87. Even though you are doing well in both general courses, these can pull you down badly.

Thank you. Yeah, you guys are right. 2% in 20% is really nothing. Now I understand. We still have 30% and 50% tests left. I was a real worried because ppl said "your mark is not important but your rank" - So... and this teacher knows me as I came 1st in Year 11 Ext 1 last year and Ext 1 this...

Oh, okay so you are saying 2% is really nothing??? As I said before, we have 30% and 50% tests left... only 2... :((((((((

But I mean do you think 3~4 mark in 20% assessment is a very big gap?

Hi all, Ive got 36/40 (3rd) but the top mark was 40/40, second 39/40. and this one worth 20% towards our internal... I am worried about my ranking... Am I really behind? Do you think I can catch up (ie. 1st)? My teacher knows that I made silly mistakes (It was a pretty easy test) and said...

Hi all, Ive got 36/40 (3rd) but the top mark was 40/40, second 39/40. and this one worth 20% towards our internal... I am worried about my ranking... Am I really behind? Do you think I can catch up (ie. 1st)? My teacher knows that I made silly mistakes (It was a pretty easy test) and said...

Hi all, Ive got 36/40 (3rd) but the top mark was 40/40, second 39/40. and this one worth 20% towards our internal... I am worried about my ranking... Am I really behind? Do you think I can catch up (ie. 1st)? My teacher knows that I made silly mistakes (It was a pretty easy test) and said...

Hi All, I have one more question: The question was find sqrt of (z) Hope I did not make algebra mistake but I've got z = something like 3x + 4 in this case sqrt of (z) is sqrt of (3x + 4) but do you put +/- infront?

Anybody???

Can you find z1 to z3 in a+ib form?

Okay I am sorry. Let me rephrase that. year before, thus 2010.

Did not say what the |z1| is. 8 u^2 is 8 unit square. So I think since it is a square, a side must be = 2 root 2? so 2root2 times 2root2 = 8???

Okay but how can you sketch x=0 and y>(equal to)0 on one graph paper?

Complex Number Vector Sorry, I am not 100% sure but... it was a vector question: OABC is a square (where A =z1 B=z2 C=z3) obv. 0 = (0,0) Arg(a) = pi/4 Area of this square is 8 u^2. I think Ive got this but can I just double check with you guys~? Thanks.

BUt I ve asked the BOS and they said that my new school cannot look at my past, they can only look at my current ones. But it seems that they know my previous mark...

Yeah... :(. but just please answer my question...

So x=0??? but seaning said it is wrong?

Sorry, I am not 100% sure but... it was a vector question: OABC is a square (where A =z1 B=z2 C=z3) obv. 0 = (0,0) Arg(a) = pi/4 Area of this square is 8 u^2. I think Ive got this but can I just double check with you guys~? Thanks.

So, wait, what is the answer then?

I have done my HSC last year back in 2010 but would like to redo this year. But my question is - I know that my previous school can look up my HSC marks but what about the new school? Can they also look up my 2010 HSC results? I am waiting for your reply.