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Yeah, reckon I screwed up Eng Adv. Then I checked the HSC mark and which percentile it equates to. Then I realised I'm fine, considering my internal rank gives me an assessment mark of about 91-2. :)

Of course. OP, whenever you have a function of a function, the chain rule must be used. I just did it more systematically so you'd understand.

\frac{d}{dx}(ln(\frac{x}{x^{2}+1})) \\ \\ \text{When differentiating logs, it's just} \frac{d}{dx}ln(f(x)) = \frac{f`(x)}{f(x)} \\ \text{So first we differentiate} \frac{x}{x^{2} + 1}, \text{ using the quotient rule, which gives us:} \frac{1-x^{2}}{({1+x^{2})^{2}}{}} \\ \\ \text{And then we...

The focus is (0,a). So find the line which foes through Q and (0,a) and that's your focal chord.

A guy from our school has a pretty good chance at getting first this year. Hopefully we can top 2 years in a row. :p

They don't. Refer to the above post.

You could've said a lot for Q28, as long as you had more than 1 or 2 policies, it's fine to leave others out.

It was just 1 mark, don't beat yourself up over it.

1: 14/15 2: 14/15 3: 13/15

Easy exam.

Use the identity: tan(2x) = 2tanx / [1 - tan^2(x)] to simplify the expression and it is much easier. You should get 1/2 - tan^2(x)/2 after simplifying which is easy to integrate.

Okay, thanks for that!

You can definitely use those abbreviations.

Hey guys, How do I do this integral? \int e^xln(x) What I do is: \int e^xln(x)dx\\ \\ =e^xln(x) - \int e^xx^{-1}dx \\ \\ = e^xln(x) - \left [ e^xx^{-1} + \int e^xx^{-2}dx\right ] \\ \\ = e^xln(x)- \left [ e^xx^{-1} + e^xx^{-2} + 2\int e^xx^{-3}dx \right ] \\ \\ = e^xln(x)- \left [ e^xx^{-1}...

The question 6 in that paper wasn't even a very hard question - in fact it wasn't even the last question of the 1993 (i think) paper, it was Q7. I'm thinking like the top 25% of the state could get the last questions in this.

Chatswood is always crowded. Try UTS/USYD/State. Macquarie is usually fairly crowded but you can still get places to study.

Most do, that's the point of the trial exams, but I think that Sydney Grammar does it pretty well.

Can't you do 13 units? That way, if you want to drop your 4th unit of maths, or Chemistry, you can when you really know what you want to do. It beats asking people you don't know and don't know you over the internet.

cos(5x) = cos(2x)\\ \\ \text{using the general solution:} \\ \\ 5x = 2n\pi \ \pm \ 2x \\ \\ \therefore 7x= 2n\pi \ \ or \ 3x = 2n\pi \\ \\ so \ x = \frac{2n\pi}{7} \ or \ x = \frac{2n\pi}{3}

Nope they're different. When you talk about dissociation, a molecule can break into different (either charged or neutral) species. For example AB ---> A + B Whereas for ionisation, the molecule MUST break down into ions. For example AB ---> A+ + B- Ionisation is a form of dissociation.