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1) s = ut + 1/2at^2 u = 0 (initial velocity being 0) t = 5 (given) a = -9.8 (gravitational acceleration) s = 0--4.9(25) s = -122.5 Therefore 150 - 122.5 = 27.5m then v = u + at v = 0 - 9.8(5) v = -49m/s 2) 1st Stone...

A particle is brought to top speed with an acceleration which varies linearly as the distance travelled. It starts from rest with an acceleration of 3ms^-2 and reaches top speed in a distance of 160 metres. Find: (a) the top speed, (b) the speed when the particle has moved 80 metres...