geometrically tan Theta represents the gradient of a line.
if the line is y -y(0) = m(x -x(0)); then m is the gradient of the line;
as gradient equal rise/ run, i.e. opposite side/ adjacent = tan(theta);
hence m = tan(theta);
You solve the question if u know what m or theta is
If you want to get good marks, don't use the textbook,
For the trial exams and half yearlies Teachers usually don't put similar types of questions from recent hsc papers (except maybe for Q9 or 10). My advice is to have a go at the 1986 -1992 past papers. It helped me so much that i got 119/120...
first use the remainder theorem, i.e. Q(1)=o, or (x-1) is a factor of Q(x)
therefore: 1+p+q -5 +1 =0
p+q=3
Then using longdivision:
u get Q(x) = (x^2 + 2) B(x) +R [ where R is the remainder and B(x) = x^2 +px +(q-2)] ]
R= -x(5+2p) -2q +1 [now equate...
Yeah they come in the mail, but u can get the abbriviated version on students online after results are relesaed
i did alright at chem, test wasn't too bad
sorry about the cut on fb, i gues that was a little harsh but i think woody has aldready had alll the mickey taken out of him