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3 days this semester but I'll probably have to go 4 days next semester :(

What is the isbn for Accounting Information for Managers - Business Reporting for Decision Making textbook?

what is the isbn for the accounting - Business Reporting for Decision Making textbook?

Is the accounting textbook still available? If so, what is the isbn for the one you have?

Is the accounting textbook still available? If so, what is the isbn for the one you have?

I want to buy second-hand textbooks but I was wondering whether it mattered if the ISBN was different from the ones on the textbooks sold at connect books. Would everything in the textbook still be the same?

Find the turning points and determine their nature for y=sin(x-1) for 1<=x<=2pi+1

i don't know...i got it off a sheet my teacher wrote.

Question: Show that the maximum value of <a href="http://www.codecogs.com/eqnedit.php?latex=\frac{\ln x}{x}" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\frac{\ln x}{x}" title="\frac{\ln x}{x}" /></a> is <a href="http://www.codecogs.com/eqnedit.php?latex=\frac{1}{e}"...

<a href="http://www.codecogs.com/eqnedit.php?latex=3-2cos^{2}x-3sinx = 0" target="_blank"><img src="http://latex.codecogs.com/gif.latex?3-2cos^{2}x-3sinx = 0" title="3-2cos^{2}x-3sinx = 0" /></a>

actually i wrote the question wrong it's actually 3-2(cos(x^2))x - 3sinx =0 and i got it mixed up with 2sin(^2)x + cos x -2 = 0 mind doing both of them? both are between 0 and 360 degrees

whoops, yeah it was meant to be 360.

Question: Solve 3-2[cos(^2)x]-2=0 for 0 degress<= x <= 260 degrees

i) a=-4, d=-8 Sn = (100/2)[2(-4)+(100-1)(-8)] S100 = -40 000 ii) -40 000 -8 = -40 008 And the rest? lol i couldn't be bothered then. but i've done it now. check the post again. i edited it.

lol i don't know how to do it. that's why i asked.

Answer: a) a=1, d=4 Sn = (n/2)[2a+(n-1)d] = (n/2) [2(1)+(n-1)4) = (n/2) [3+4n-4) = (n/2) [4n-1] = n[8n-2] = 8(n^2)-2n b) a=3, d=4 Sn = (n/2) [2(3)+(n-1)4] = (n/2) [6+4n-4] = (n/2) [4n+2] = n(8n+4) = 8(n^2)+4n i) a=-4, d=-8 Sn =...

it should...

a=2, r=2 Tn = ar^(n-1) T20 = 2*(2^19) = 1 048 576

Answer: table of values: x -1 0 1 2 3 4 f(x) √2 √1 √2 √5 √10 √17 √[1+(x^2)] dx = (1/3)[(√2+√17)+2(√2+√10)+4(√1+√5)] = 9.2115... Question: 2(x^2) + pq + q = 0 has one root 3 times the other. Show that 3(p^2) = 32q

Question: Find the maximum product of 2 numbers whose sum is 25.