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you could use the quotient rule that way if you wanted. It's similar to the parts method. u an v are functions of x . Integrating the quotient rule. Rearranging So just using a substitution and the answer will pop out. Albeit being pretty neat, using this method is only useful in certain...

Re: Small money questionThe Ripoff finance company had the following hire purchase ag This seems more like an accounting question. There isn't any interest involved. I'm pretty sure this isn't in any way a hsc question. There isn't enough information to answer this question. Did you mean that...

ahh, well to get that third solution is pretty sucky. Who gave you that question? Also i really don't think you should approximate answers for the hsc. The only way i can see answering that is to use the lambert W function. Your answers are very close. Lambert W function - Wikipedia, the...

oh, didn't realise you gave an answer haha. guess it's correct then. As it turns out, for 2*d - d^2 *(1/2 + pi/8) to equal 1.12 (d exactly) d^2*(1/2 + pi/8) = d [2/(1 + pi/4)]^2 *(1/2 + pi/8)= [2/(1 + pi/4)] [2/(1 + pi/4)]*(1/2 + pi/8) = 1 [2*(1/2 + pi/8)]/(1 + pi/4)] = 1 (1 + pi/4)/(1 +...

ok i'll explain the second one. I normally don't do a whole question, but you asked for the solution so i'll show you and try to explain how to do these questions. **The diagram is important. look at the diagram i have attached. You should label your diagram similarly and draw it up...

did you mean An = 30000*(1.115)^n - m*{ [ a * (r^n - 1) ] / [ r - 1 ] } so An = 30000*(1.115)^n -:pirate: 4500*(1.115^n - 1)/(1.115-1) with An being the amount. The question is asking you: Over what period will the loan be repaid? So they want to know when the amount goes to zero. With...