Hi guys,
I've been stuck on this binomial theory question (find the coefficient of x^3)
HHHNNNNGGGG what am I doing wrong?
Many thanks,
Frustrated girl
Hey people,
Some of you have probably already ordered your jerseys for year 12 but our school is slowas so could you guys recommend some good quality and decently priced offers from any jersey committees?
Thanks in advance
peace out.:blink2:
How would you find he square root of
4-3x
I get up to 4b^4+16b^2-9=0 and then I'm not sure how to continue...
It would be much appreciated if anyone could lend me a hand
Hi I've attached a photo of the question because it's a bit hard to type up.
I can work the question out until the end where I'm not sure how the e substitutes.
:newburn:
Thanks in advanced!
Hi,
Find y as a function of x, if y' = 1/4x and y= 1 and y = 1 when x = e2. What is the x intercept of this curve?
If someone could explain this to me, it would be great. Thank you.
Hi,
Find y as a function of x, if y' = 1/4x and y= 1 and y = 1 when x = e2. What is the x intercept of this curve?
If someone could explain this to me, it would be great. Thank you.
Hola! Does anyone know how to do this?
Equal volumes of Silver Nitrate Solution and Magnesium chloride solution, each 0.20 mol L-1 are mixed. Determine the concentration of the ions remaining in the resulting solution.
Thanks in advance!:sun:
Hi guys does anyone know how to do this?
THANKS!
The tangent at P(2at,at2) on the parabola x2=4ay meets the x-axis at T
Show that as t varies, the locus of M is the parabola 2x2=9xy
:wavey:
Hi guys,
I''m new here.
If anyone has time could you give me a brief intro to how this website works, how I can answer questions, how do I get more rep powers? And all that jazz it would be much appreciated.
Cool thanks
Hi if anyone has time could you please help me out? x
The points P(2ap. ap^2) and Q (2aq, aq^2) lie on the parabola D whose equation is x^2 = 4ay.
Suppose that A (intersection of the tangents to D at P and Q) lies on the line containing the latus rectum of D.
Show that pq=1
HOW CAN...