$I think they want you to do it like this:$
$a) The answer wanted is $x+2y + 9 + k(2x-y+3) = 0$, where $k\in \mathbb{R}$.$
$b) We want $(0,0)$ to lie on the line, so this happens iff $0+0+9 +k(0+0+3)=0 \Longleftrightarrow 3k+9=0$, that is, $k=-3$. Substitute this in to our general form in a)...