$\noindent Here's how to do part (b).$
$Starting from $\mathbb{E} \left[X^2 \right]= \sum_{k=1}^{\infty} \frac{k\lambda^k \mathrm{e}^{-\lambda}}{\left(k-1\right)!}$, we use the change of variable $j=k-1\Longleftrightarrow k = j+1$. When $k=1$, $j=0$, and as $k\to \infty$, $j\to \infty$, so we...