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not sure it works that way...

yes thankyou goawd that was a dumb question...

thanks a lot mate! =D but just a side question, this may sound pretty stupid - a basic 2 unit question, but what are you supposed to be looking for in order to factorise the numerator in STEP 2 into the numerator of STEP3 so quickly? I see you can factor the 2 out when after you convert the...

oh damn, i forgot to put in the i, so basically unlike the previous terry lee questions, instead of the sine being imaginary, the cos is the imaginary part, so i've no idea how to simplify.... i tried factorising the i to get it into cos(a) + isin(a), but nothing happened please, i really need...

Hi here's a question that I just can't do: Q. Simplify: {[1 + sin pi/7 + icos pi/7]/[1+sin pi/7 - icos pi/7]}^7 I can't seem to see any trig rule that i can use to simplify this, help is greatly appreciated. Thanks guys

very very noice, these are gonna help in conics...

no one does, just that textbooks don't have these formulas

noice

thanks, couple more questions don't know how to do, like this one: x>0, y>0, z>0 x+y = s prove that: 1/x^2 + 1/y^2 = 8/s^2 so a solution with explanation would be immensely helpful thanks

what is the rule?

Thanks for this, just check my solution please: so (a+b)>=2root(ab) (b+c)>=2root(bc) (c+a)>=2root(ac) Now i don't know about inequality rules or what, but are you allowed to multiply everything on either side, because that is the only way i see to get the answer thanks

I'm sorry but how did you get from (a+b)/ab to (a+b)^2/ab??

do you learn these in tutor? also what is this sum to product rule? thanks

Hi guys, couple of questions i can't do with "considering the difference" Q1. Given that a+b=1, show 1/a + 1/b >= 4, for a>0, b>0 Q2 Prove that for positive no's a, b, c, d (i) (a+b)(b+c)(c+a)>=8abc (ii) (a+b)(b+c)(c+d)(d+a)>=16abcd Thanks appreciate the help

how did you get from the 2nd step to 3rd step?

That is the locus of z i.e (x+1)^2 + y^2 = 0. Here's what i got out of the question: ignore the z/z+2 part, concentrate on w, as we are finding the locus of w. Now if w is purely imaginary would t not make sense that the locus is the imaginary axis?

aaaaaaaahhh..... I seee.... thanks mate

real part: x(x+2) + y^2 = 0 (excluding (2,0) But isn't the above the LOCUS OF z, and not w?

how did you get this?

Hi I have a question here which seems pretty simple (only 2 marks) but my brain is a little fuzzled... Question: If w = z/(z+2), where z=x+iy, x,y real Find the locus of w if it is PURELY IMAGINARY Ok so here's what I did: w= (x+iy)/[(x+2)+iy] = {(x+iy)*[(x+2) - iy]}/{[(x+2)+ iy]*[(x+2) -...