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http://www.actuaries.asn.au/Sitefunctions/faq.aspx http://www.actuaries.asn.au/EducationandProfessional/Education/PathwayFellowship.aspx @OP, the websites above may be somewhat useful basically, from what I can see, a solid understanding of mathematics is ONE of the things you MUST have...

yes z = e^(0+0) - 2 = -1 is the minimum for the given domain

Q14 the way to find critical point for this question is similar to that for function of 1 variable( i.e. where f'(x)=0 ), since the function has more than just one variable, you'll need to find its Partial Derivatives find the x and y partial derivatives by regarding y and x as constants ...

it's very difficult to predict what marks you'll actually get , especially when you don't even know what exactly the subjects are about which is why the whole 'which subjects should I do' thing [and to some degree, ATAR predictions] doesn't make sense to me don't let things such as...

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Re: Semester 1 USYD Chatter Thread it hasn't changed for both semesters in 2011, at least for the subjects I did

@OP, next time ask your friend to integrate e^(-t^2) dt , or integrate sin(t^2) dt

where did you get that question from?

+1 Drongoski is highly recommended

could some one tell me what's going on here [as an experiment, I know it's not exactly 'Maths ']: (using a calculator) store A as 7^(1/7) ans=A then ans=A^ans, the 10 digits displayed don't seem to change at all after 30 iterations or so and it is 1.530140119 or 1.53014011947213 (from...

is it ?

Dunno if this qustion is related, but seems interesting : x^x^x^x^x^x^x^x^x^... = 7 ( infinitely interated ) Find x

has your teacher taught this ?

extraterrestrial angle?

yes [a simpler example] would you agree: d/dx(x^2)=2x and (1/2)*d/dx(x^2)=x ? in your question, a is just a constant(a=2,in this particular case) , so is ln(a) d/dx(a^x)= ln(a)*(a^x) then (1/ln(a))*d/dx(a^x)=a^x

many books use this kind of abbreviations, which looks fine to me as long as you don't get a fussy teacher marking your assessments, or in the HSC I'd use the abbreviations in practice ,but remember what the full version is and use that in real exams

you may be able to get away with shortening the theorem, but how brief is too brief ? I think it's too hard to say, so I'd probably write down the whole thing

what would you get when you integrate both sides ?

it's an even function ,i.e. f(alpha)=f(-alpha) if alpha is a real zero, so is -alpha there is only one real solution -----> then it must be x=0, substitue and we get k^2-1=0 , k= 1 or -1 these two values of k would give x^4 - x^2=0 and x^4 + 3x^2=0 respectively the 1st eqn has 3 real...