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I'd say the common mistakes are getting the negatives the wrong way :D Yeah it would depend on the types of questions.

Honestly you ask way to many questions about this, it's best that you wait and see when you start doing 4U math yourself instead of speculating about it.

and the last question is integrating the function with limits 0 to 4

I think you typed it wrong lol, is it a - or +?

Actually even in 2U math has these kinds of problems.....(the last questions of course) They just be like "prove this" without giving any hints.

The harder questions in Ext 1 encourage that sort of approach as well (maybe to distinguish between the Ext 2 peeps and "only" Ext 1 ) And by thinking critically, for example you might have to figure out the best method or the best formula/identities , you could end up actually getting an...

Re: First Year Uni Calculus Marathon wait what? I don't know if it's legit lol

Re: First Year Uni Calculus Marathon $ a) Let g(t) = \sqrt{1+t^4} \\ \\ \therefore f(x) = G(x^2+x) - G(2) \\ \\ f'(x) = (2x+1)g(x^2+x) - 0 = (2x+1) \sqrt{1+(x^2+x)^4} $ b) at $ \ \ f'(x) = 0 \ \ x = -\frac{1}{2} $it's a minimum point since the slope function goes from negative to positive...

ehh.. it depends on the paper I guess, my year (2013) was apparently considered a tough paper, so like 78 would align to an E4

Dammit, who are you ? Bump... pls help

no

$ For any $ \ \ 0<p<1 \ \ $and$ \ \ r \ \ $ a positive integer, the probability function $ \\ \\ f(x) = \binom{r+x+1}{x}p^r(1-p)^x \ \ \ x = 0,1,2 ... \\ \\ $defines a random variable X$ \\ \\ $Show that the moment generating function$ \ \ m_X(u) = \mathbb{E}(e^{ux}) = \\...

just try your best and boommmm, you're in :) But yeah for a low ranking school like mine, they just look at your marks lol.

One advice is to skip the questions that you can't do straight away and get back to them later, this may sound obvious, but the issue is that the question could somehow "absorb" you while you're not really "warmed-up" in the beginning of the exam,which means you're working a bit slower than what...

hehe if you plan to do 2nd year stats, then some of these materials are useful, otherwise you're kind of wasting your time

Re: HSC 2016 4U Marathon ewwww no.

Re: HSC 2016 4U Marathon Oh wait I was right, is the answer 4 \theta = 2k \pi $ Where k is an integer but 0 $ \\ \\ \theta = k \frac{\pi}{2} EDIT: This is because from the above equation the denominator 1-cis(\theta) can't be 0 which is why theta can't be 0, dammit how did I not see that?

Re: HSC 2016 4U Marathon I'm bored so here's how you do itttt $Consider$ \ \ 1 + cis(\theta) + cis(2 \theta) + cis(3 \theta) = 0 \\ \\ \frac{1-cis(4 \theta)}{1- cis(\theta)} = 0 \\ \\ $Equating the real parts implies that solving for $ \cos{3\theta} + \cos{2\theta} + \cos{\theta} + 1 = 0 $...

??? for Q 2 you use the double angle formula for both (tan 2theta), then you go through the tedious algebra to simplify to the RHS. (hint multiply top and bottom by (1-tan^2)(tan))

essentially the identity to remove the value 1.