Search results

let angle CBA =x then angle PCA = x (alternate segment, a tangent at C?) and because CKAP is cyclic then angle PKA = x that's all you need: CB and PK are both inclined at same angle to AB (ie x) and are thence parallel. result follows.

Of course Heron's rule is not in the syllabus. The syllabus is a statement of minimum requirement. Good students will have no problem soaking up simple formulae such as this and using them to their advantage. This is where good teaching come to the fore. Teachers need to know far more than...

lets use the diagram above. The 13, 14, 15 triangle has an area of 84. (Heron's rule*) So the height (half of the common chord ) is 12. Hence 24. <?xml:namespace prefix = v ns = "urn:schemas-microsoft-com:vml" /><v:imagedata o:title=""...

There have been some changes. Geometry was dropped (HUGE MISTAKE) and then reappeared about 1984 HSC. They stuck it all in one question and the markers had a nightmare. Now they ask less and stagger it about or incorporate it into other questions. I have seen Teachers who did HSC in times of no...