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getting a life would really help.

just use u=3x then du/dx=3 therefore dx=1/3 du then find 1/3 S sin^2 (u) 1/3 { 1/2 u - 1/4 sin2u } sub u back in you get 1/2x-1/6sin6x that was simple.

welll we all know how people abuse their freedom of speech... good on you guys.

ronkkee i know, i just ignored it, because i know tan90 dont exsist, soo yeh xD.... these types of question you just need to know your identites.

its pi/4 .. they wont give you limits between pi/2, because the top of tan^2n-2 has to equal to 1.. therefore it must be pi/4... i never said anything about pi/2 the guy put it there. i showed him how to do it.:read:

If they remove conics, i wont be called Conics2008, I dont see why you guys hate that topic, it just like locus, its was just a piece of cake... I agree that topic is full of shit, but its a cool topic.

ok this is what you do write (tanx)^2n as (tanx)^2n-2 . tanx^2 therefore tanx^2 = sec^2x-1 therefore when you expand it, you will get tanx^2n-2 = I n-2 and tan^n-2 sec^2 take I n-2 to the other side. and then intergrate tan^n-2sec^2 using u=tan when you do that you will...

This is the question. In 1970 I began collecting calendars and I have done so every year since. I will stop collecting when every subsequent year can be served by at least one of the calendars I have already collected. What is the last year that I collected a calendar? Thanks.:jaw:

ok i give up, i had enough of that question, my mind doesn't work for easy quesitons... soo i think ill pass.. because that equation has no integer roots or what so ever.. anyways, im out.. ive been playing too much games here.. take care. thanks for the questions =)

3units did you factor out x and made it look like this x(x^100+x^50+1-1/x)

Tommy conics. dy/dx = x^2/2y therefore gradient = 9root2/8 find the stupid line.. this is the equation. 36xroot2 - 32y -54+8root2 =0 then use this and solve it together with the circle equation.. am i on the right track or did i go off track.

do you assume that alpha is one of the roots and then you sub it in, a^101+a^51+a=1 factor out a gives you a^100+a^50+1 = 1/a then i dont know whats going on ??

Move out, and become a boy ( male )

I would struggle hardcore style at general, alot of people at my school do general and always ask me to do their quesiton, buts its freaking HARD I tell ya. Its very complicated general maths, compared to 4unit and 3unit..

hey im not going to finish it ill just tel you what you gota do, see the base , you can write it like this 4S1/ (x-1)^2 -2 and then just integrate 1/(x-1)^2 -2 and then your done.. ok then ill tell you use u=x-1 when your done , break up your fraction.. then integrate one by one...

i already gave my answer to your intergal.. its just 1 by inspection !

hmm ok, different working out mine to yours.. ohh well who cares.. these types of question never come in the HSC.. soo i wont bother with my answer.

use this : S between a and -a f(x) dx = S between a and 0 f(x) + f(-x) when you do that you will get 2 fractions, then times e^x / e^x with one of them... to remove that e^-x when you do all that you will get S 1 to 0 of 1 dx therefore (x)1 and 0 is equal to 1...

the other thingy doesn't have to be standing on the circumference, show me your diagram.. you can also have the circle and those two lines which make pi/4 or 3pi/4 be made at the center of the circle.. sorry, i dont know how to draw good on paint, it turns out really bad. post your diagram.

Heres a complex numbers question. If | z- 6i| = 5 Prove that arg ( z-4-3i / z+3-2i ) = pi/4 or 3pi/4