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lol I suspected that it was a joke but I decided to post the above one anyway

SRS? (2x+3)(4x^2-6x+9)

the tan pi/8 one I forgot to root it. It was an extremely stupid mistake.

Would 83/84 align to 99 or 100?

lol, absolutely not as in correct

No, I just left it as tan^2 (pi/8)=3-2rt2

nah, not 100% found one stupid mistake

Shit, tan pi/8 question I forgot about the squared.... 1mark lost as well... 83/84

I was thinking about the same question too when I first saw Terry Lee's solution

I loled at this.

That's exactly why I want to see it.

Mine is 25th (UNSW) Why did you make it early?

Ah, yes, your FAVOURITE option, shipwrecks That's yucky. But anyway, if I didn't make any stupid mistakes, which is unlikely since I found and fixed 2 errors in the last 3 minutes, I should get pretty much everything correct.

LOL shut up! Don't criticise me.

LOL I did that. I didn't notice that the linear relationship could be utilised when I was in the exam room. But still had time for everything so I guess it doesn't matter.

Wasn't the answer 100 days?

Here's my solution. Consider triangle SPR angle QSR=angle SPR+angle SRP (an exterior angle of a triangle is equal to sum of its opposite interior angles) Hence, using given denotations, phi=theta+angle SRP Now for PT>0, (I.e. P is not the same as T) angle SRP>0 This means theta<phi...

The answer to circle geo in Q7 was very simple if you knew how to do it Btw, I'm surprised that you didn't mark anything on your paper

How did you go in MX1?

It's the new exam committee