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^ yea this guy got it right

thanks guys i understand part 1 now but i think u all got part 2 wrong Function Grapher Online graph it there

i) Solve cos3@-cos@=2sin@ for 0<@<2Pi ii) Solve 2|x|-|x-2|>2

yes he does

0+0i is a solution and -1+0i guy above made a mistake

prove Z^2+Y^2+X^2=ZY+YX+ZX where Z, Y and X are any three complex numbers that represent the vertices of an equilateral triangle

not finding it too difficult so far

i have fitzpatrick; pretty basic, a gud starting point tho cambrige; harder sort of questions terry lee; a sad joke at best

i) If z is a complex number such that z=k(cos@+isin@), where k is real, show that arg(z+k)=@/2 ii) Deduce that if z1, z2 and z3 are ANY three complex numbers at the vertices of an equilateral triangle then (z1)^2+(z2)^2+(z3)^2=z1z2+z2z3+z1z3 iii) Given that 1+z+z^2+z^3=(1-z^4)/(1-z) and that...