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Really? Your name? St. Mark's school I bet?

Mark Ishak is a pain...

Haha I think I love you.

Re: Ext 2 Past Papers + Answers I think it's more than obvious that no-one can get all the answers...especially a student still studying the course.

I'm going. Doing Crime Fiction. The be-all and end-all of gayness.

Can you be sure that you won't be marked down for bad working out?

Differentiation of Sec x = Sec x Tan x. Differentiation of Cosec x = - Cosec x Cot x.

No-one wants you here if you're going to be immature idiots.

Cos x/(Sin x)^2 = Cosec x Cot x. Integration(Cosec x Cot x) = - Cosec x.

Previous post edited for your sake.

For these things, I would suggest just finding the stationary points (even approximately) and intercepts, then draw the general shape. If the curve is a polynomial, all that's needed is to add an intercept at x = 0 .

Really...a definition is useless.

Prove every odd function is zero at x = 0: f(-x) = -f(x) for x = 0, so f(0) = -f(0). 2f(0) = 0, so f(0) = 0, proven as required. Someone else can do the rest for now.

Refer to the last question of the Terry Lee vectors exercise for a purely algebraic answer.

Total arrangements of 12 people around a circular table = 11!. Arrangements with your condition = 11! x 36/55 = 26127360.

The inequality only applies for positive integers anyway.

Those extension questions are the perfect resource for consolidating problem solving skills...I did them after finishing the extension 2 course.

I think you mean sum of roots = product of roots for the equation with roots Tan A, Tan B and Tan C...

Oh deary me...I completely misread the question. My mistake, I know what you mean now.

\\$Sides of a triangle add to 180 degrees, so $ A + B + C = 180.\\ A = 180 - (B + C), Tan(\frac{A}{2}) = Tan(90 - \frac{B + C}{2}) = Cot(\frac{B + C}{2})\\ Tan\frac{A}{2}Tan\frac{B}{2}\cdot Tan\frac{A}{2}Tan\frac{C}{2}\cdot Tan\frac{B}{2}Tan\frac{C}{2} =...