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im confident that is the method but im pretty sure i said 3A = ... which was a blue on my part.

you just had to use the ratio they gave you. it ended up... A/3 = Ae^(-kt) so divide through by A 1/3 = e^(-kt) t = ln(1/3) / -k i think i used 3A in my haste but thats how you do it...

As im only doing it now with you i cant really comment on its effectiveness but ill throw my method out there anyway.. i just get the syllabus and distinguish it by colour in word, then i dig out all my notes and gradually go through it summarising to the required information in a different...

in your working just state what you are using, ie g=10ms^-2 and they cannot take marks off. no-where in the course does it specify what gravity definitively is, remember it changes (however slightly) around the world anyway. I (my opinion, havn't checked) believe that if you stated in your...