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I think youre supposed to make the null hypothesis equal to something but it doestn really matter so I guess H_{0}:\ C\geq\ 95, H_{a}:\ C<95.\text{where C is the cholesterol level}\\ t_{obs}=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}}}\\ t_{obs}=\frac{89.02-95}{\frac{12.9}{\sqrt{6}}}=-1.14\\...

we will see

What I'm aiming for or what I think I got?

Has anyone done econ204 or acst212?

Nicu

Lol I did so much of that in acst152 but harder versions, like changing interests rate, missed payments, changes in taxation etc throughout the term. fkn annoying lol

People have said it's an easy HD for acst students... But ill jsut do my best and see what happens. Oh I did have one more question. I think I have to choose some units further on down the degree, is it possible I can pick maths? It's not explicitly in my program after year 1. Here's a copy of...

Ah ok cool. Nah im pretty dedicated and I was planning on continuing uni/work over the break.

All this stat stuff looks so much more complicated than what I've done. Only done stat171 where had z, various t tests, and chi squared test for independence and GOF test... rip

What's the pace like. Cause I've enrolled in acst101 so I will only have to do 3 subjects in year 2 semester 1. All my subjects are CT exemptions then so I thought doing 3 instead of 4 would be a better idea.

Have any of you guys done summer school before?

ALL DONE BBY! woot :)

What degree are you doing?

2 down 2 go. Got my hardest one tomorrow tho. How's everyone faring?

If the shape has a rectangular cross section then the area for a particular slice can be given by the product of two lines i.e. A=lw. so you can just as say the width of the base of the shape to be w=mh+c and youll be given measurements to evaluate m,c. Similarly you can do the same for the...

Hey, I found this last year. http://mathext2.web.fc2.com/. It hasn't been updated though. Here's another one (got this from a friend who got it from the school captain of Ruse) https://onedrive.live.com/?authkey=%21AHRJRolSQWmYCAQ&id=34CAF24F73803652%21153&cid=34CAF24F73803652 . I don't know...

Ahhh ok cool. Thanks heaps.

Aaah ok. So my mistake was not looking at it for all multiples of 9 rather than trying to find a single value. So you've just done \2^{2n}+6n-1=9r\ \text{such that}\ r\in\mathbb{R} ?

Hey I'll try to help but I haven't done this for a while. (i)\(b-1)^{2n}=\binom{2n}{0}b^{0}(-1)^{2n}+\binom{2n}{1}b^{1}(-1)^{2n-1}+...\\+\binom{2n}{2n-1}b^{2n-1}(-1)^{1}+\binom{2n}{2n}b^{2n}(-1)^{0}\vspace{0.5cm}\\ (ii)\ \text{This is equal to}\1-2nb+\binom{2n}{2}b^{2}-...-2nb^{2n-1}+b^{2n}\\...

Need number of b6/e4 in preivous years