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jnney

jnney

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  • _deloso
    well you need to find the c of cacl2. you use c=n/v find the moles of the cacl2 only in 0.71 g which you know how to do. now for v, you need to add the 2h2o with the 250 ml. to get this, multiply the mole of cacl2 by 2 because every mole of cacl2 releases 2 mole of water (cacl2.2h2o) now convert this mole to grams and 1 gram=1ml. add this to the 250ml and find the c
    ohexploitable
    same way as you would for a normal equation

    i.e. |x+3|=|x-1|

    x+3=+(x-1) or -(x-1)

    -----

    i don't recall much of year 11 stuff so idk
    ohexploitable
    oohhhhh, i'm interpreting it wrong haha (need more sleep i guess lol)

    you just let P be (x,y), then substitute it into the distance formula for PA and AB so,

    "PA^2+PB^2=4 where A=(3,-1) and B=(-5,4). Find the equation of the locus of P."

    PA^2=(y+1)^2+(x-3)^2
    PB^2=(y-4)^2+(x+5)^2

    PA^2+PB^2=4

    (y+1)^2+(x-3)^2+(y-4)^2+(x+5)^2=4

    now simplify ;)
    ohexploitable
    are you sure you typed first one correctly?

    assuming PA and PB are distances, PA^2+PB^2 cannot be 4, in fact the smallest value for PA+PB is root 79
    ohexploitable
    3rd one: perp distance formula again, equate distance from both lines i.e.

    (3x+4y-5)/5=(5x+12y-1)/13, simplify etc.
    4025808
    oh thanks btw :)

    yeah I'm fine... just trials atm, need to seriously memorize the heck out of english stuff =_=
    Bored_of_HSC
    Hey, long time no talk. How've you been finding school?

    As for the question:
    You just you "E= .5mv^2
    so .5 times 1000 times 15^2

    That's initial kinetic energy

    After crashing it's kinetic energy is 0

    (don't trust me too much though, physics is my achilles heel)
    Omnipotence
    Well Yr 12 has/will be starting soon. I'm not too sure but there are classes on Thursday (after school), Saturday (morning) and Sunday (throughout day).
    4025808
    I used to have phys tutoring till i dropped phys...

    i had a private tutor, $60 for 1.5 hours. My tutor helped me in 3U + 4U maths as well..
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