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Prelim 2016 Maths Help Thread (1 Viewer)

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leehuan

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See the 2U/3U syllabus or a textbook for the derivation
Emphasis on this. Still waiting for you to drop the stubborn attitude with textbooks @ eyeseeyou. It's insulting.
 

Trebla

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Well.....I've got notes with me atm and it doesn't have the derivation
What textbooks do you have?

Did you cover the derivation at school?

Did you look at the 2U/3U syllabus? There is actually a derivation in there.
 

eyeseeyou

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What textbooks do you have?

Did you cover the derivation at school?

Did you look at the 2U/3U syllabus? There is actually a derivation in there.
old fitzpatrick

And PDF's of new fitzpatrick and Cambridge (don't have atm)
 

eyeseeyou

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What textbooks do you have?

Did you cover the derivation at school?

Did you look at the 2U/3U syllabus? There is actually a derivation in there.
old fitzpatrick

And PDF's of new fitzpatrick and Cambridge (don't have atm)
 

Paradoxica

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Well, EYESEEYOU, seeing as the sums to products and vice versa identities are not in the syllabus, you should not expect your notes to contain them.

Like I said, prove them yourself.
 

eyeseeyou

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Well, EYESEEYOU, seeing as the sums to products and vice versa identities are not in the syllabus, you should not expect your notes to contain them.

Like I said, prove them yourself.
There was no need to capatalise my name in bold and enlargen it
 

eyeseeyou

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Well, EYESEEYOU, seeing as the sums to products and vice versa identities are not in the syllabus, you should not expect your notes to contain them.

Like I said, prove them yourself.
There was no need to capatalise my name in bold and enlargen it
 

eyeseeyou

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Okay I am very confused with this:
1. Find the inverse function f^-1(x) of each function and verify that f^-1(f(x))=f(f^-1(x))=x
a. f(x)=(x-2)^2, x is less than or equal to 2
b. f(x)=x(x+2), x is greater than or equal to 1
c. f(x)=(x-1)^2+2, x is greater than or equal to 1
I can't seem to get this
 

leehuan

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I only lookied at it for like 5 seconds b/c I didn't have the time to fully look at it
Lol what

You have time to type questions up for BoS and wait but you merely glanced at the textbook examples?
 

leehuan

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I'll do the f(x)=x(x+2) bit (as in finding the inverse) though because that one might be a bit annoying unless you've seen how to apply the quadratic formula



f(x) has domain x≥1
So
f-1(x) has range y≥1

 

eyeseeyou

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So I did this and am so confused:

f(x)=(x-1)^2+2,x≥1
y=(x-1)^2+2,x≥1
y-2=(x-1)^2,x≥1
x-2=(y-1)^2,y≥1
(y-1)^2=x-2,y≥1
y-1=√(x-2) ,y≥1
y=√(x-2)+1 ,y≥1

Could some1 tell me what I need to do next?
 

leehuan

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So I did this and am so confused:

f(x)=(x-1)^2+2,x≥1
y=(x-1)^2+2,x≥1
y-2=(x-1)^2,x≥1
x-2=(y-1)^2,y≥1
(y-1)^2=x-2,y≥1
y-1=√(x-2) ,y≥1
y=√(x-2)+1 ,y≥1

Could some1 tell me what I need to do next?
The inverse function looks right but where you square rooted, you should put the ± sign in then drop it out the next step. At least, in my opinion.

You could potentially get away with it though because you continuously stated y≥1
_________





 

eyeseeyou

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The inverse function looks right but where you square rooted, you should put the ± sign in then drop it out the next step. At least, in my opinion.

You could potentially get away with it though because you continuously stated y≥1
_________





I got y=1+ Squareroot of (x-2)

Is that the answer?
 
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