aDimitri
i'm the cook
well most of them are not to be taken seriously in the slightestmost of them
well most of them are not to be taken seriously in the slightestmost of them
never take the internet seriouslywell most of them are not to be taken seriously in the slightest
http://www.imo-official.org/country_individual_r.aspx?code=AUSUm who was the imo guy?
actually only 2 are in year 12 in NSWhttp://www.imo-official.org/country_individual_r.aspx?code=AUS
1/6 chance
But 'imo guy' said he skipped q14 and 15 and went straight to 16 so there's that...
OMG I sat next to this guy in the exam :|http://www.imo-official.org/country_individual_r.aspx?code=AUS
1/6 chance
But 'imo guy' said he skipped q14 and 15 and went straight to 16 so there's that...
Someone's impatientso... when can we expect results?
i care more about bos trials than HSCSomeone's impatient
Why?i care more about bos trials than HSC
HSC too ezzz for himWhy?
because i'm going to get my course fairly easily then never care about my HSC again. whereas i thoroughly enjoyed sitting this examWhy?
Next Tuesday after paper 2 we will release 2U, 3U and 4U results.so... when can we expect results?
thanks very muchNext Tuesday after paper 2 we will release 2U, 3U and 4U results.
The original question had a typo, so you had to actually calculate it. (I did it via differentiation of the geometric series formula, a trick you see later in the exam incidentally).Can someone help me with q10 multiple choice? I seriously have no clue
The last option was supposed to be - 1-n.Can someone help me with q10 multiple choice? I seriously have no clue
Did you differentiate the geometric series formula or did you use some other trick for accounting for the linearly increasing coefficients? (The terms in the series being kz^{k-1}).The last option was supposed to be - 1-n.
This one was my fault. In the construction of the question, I summed two geometric series, one including w and another with w bar. I forgot though that I had to subtract 1 from both sides.
Ah yes, the differentiation and iterated sum methods were what came to mind, forgot about the (1-x)S(x) trick. I guess that reduces it to a GP, cool .To get the closed form initially I used the standard differentiation trick, I think in Trebla's solutions he also used the sum of the sum of gp method. There's a third way I know of using (1-x)S(x) trick that handles it nicely.