MedVision ad

Demento's Year 10 maths practice paper thread (4 Viewers)

Fawun

Queen
Joined
Jun 23, 2012
Messages
1,270
Gender
Undisclosed
HSC
2014
Re: 2012 Year 9 &10 Mathematics Marathon

Haha, sorry about that. It's not the sides (i indicated that they're parallel). The 2 dots suggest the two angles are equal in the diagram.
idgi

So can I just replace the second line in my proof with "Angle BAC = Angle BDC (given)" and make it AAS lol
 

HSC2014

Member
Joined
Jul 30, 2012
Messages
399
Gender
Male
HSC
N/A
Re: 2012 Year 9 &10 Mathematics Marathon

fuck you -_-

Also, for question 2 b, is this right for the proofs?

In Triangle BAC and CBD,

Angle BDC = Angle CBA (alternate angles are equal in parallel lines)
BA = DC (given)
BC is common

Therefore, Triangle BAC and CBD are congruent (SAS)

????
First line you made a typo.
Second line is wrong. It is given that they are parallel, nothing more.
Third is fine.
 

Fawun

Queen
Joined
Jun 23, 2012
Messages
1,270
Gender
Undisclosed
HSC
2014
Re: 2012 Year 9 &10 Mathematics Marathon

First line you made a typo.
Second line is wrong. It is given that they are parallel, nothing more.
Third is fine.
oh my gosh this thing is so frustrating
 

Fawun

Queen
Joined
Jun 23, 2012
Messages
1,270
Gender
Undisclosed
HSC
2014
Re: 2012 Year 9 &10 Mathematics Marathon

i give up
 

theind1996

Active Member
Joined
Sep 10, 2011
Messages
1,256
Location
Menai
Gender
Undisclosed
HSC
N/A
Re: 2012 Year 9 &10 Mathematics Marathon

Wait did I do question f correct?

m^4 - 5m^2 + 4 = 0

m^4 - 5m^2 = -4

m^2 (m^2 - 5) = -4

m^2 = -4 (no solution)

m^2 - 5 = -4

and then solve for m?

failing this hard
solve the quadratic by subbing in a letter as m^2 (like u or z or w/e).
 

Fawun

Queen
Joined
Jun 23, 2012
Messages
1,270
Gender
Undisclosed
HSC
2014
Re: 2012 Year 9 &10 Mathematics Marathon

Umm, I don't recall the Q asking for this.
I meant using pythagoras to find the height so I can use the area (height x base) for the parallelogram
 

HSC2014

Member
Joined
Jul 30, 2012
Messages
399
Gender
Male
HSC
N/A
You will come to realise Fawun that a math question can be tackled in countless of ways, and answered correctly. It's just about finding the most efficient way. :) Personally I didn't use pythag but it could? work. Just briefly looking at the question I'm going to say that its invalid, but meh. Maybe
 

Fawun

Queen
Joined
Jun 23, 2012
Messages
1,270
Gender
Undisclosed
HSC
2014
Re: 2012 Year 9 &10 Mathematics Marathon

I meant using pythagoras to find the height so I can use the area (height x base) for the parallelogram
lol my bad didn't read question properly
 

kazemagic

Member
Joined
Feb 8, 2012
Messages
626
Gender
Male
HSC
2014
Re: 2012 Year 9 &10 Mathematics Marathon

I meant using pythagoras to find the height so I can use the area (height x base) for the parallelogram
w8 nvm u cant use pythagoras, it doesnt say its a right angled triangle LOL
 

Users Who Are Viewing This Thread (Users: 0, Guests: 4)

Top